A K2Cr2O7 +b KCl + c H2So4. = gt; x CrO2Cl2 + y KHSo4 - EduRev Since each CrO2Cl2 molecule contains 2 Cl atoms, x=2 implies 4 Cl atoms on the right side Finally, let's balance the hydrogen (H) and sulfur (S) atoms: a) When c=6, we have 6 H atoms on the left side To balance this, we need 6 H atoms on the right side as well Since each KHSO4 molecule contains 1 H atom, y=6
Name the product obtained when toluene is treated with cro2cl2 in . . . When toluene is treated with Cro2Cl2 (chromyl chloride) in the presence of CS2 (carbon disulfide), the product obtained is benzaldehyde The reaction is known as the Etard reaction or the chromyl chloride oxidation of toluene
Howto find hybridastin of cro2cl2? - Brainly. in Answer: Explanation: The chemical name of the compound with structure CrO2Cl2 is chromyl chloride It is a coordinate compound with tetrahedral geometry It is an inorganic compound The chromium atom in CrO2Cl2 undergoes d3s hybridisation The oxidation state of chromium in chromyl chloride is +6 The electronic configuration of chromium is given as [Ar]3d54s1 In d3s hybridization of chromium
Oxidation state of Cr in CrO_2Cl_2 is - Toppr Let x be the oxidation state of Cr in CrO2Cl2 Since, the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0 x+2(−2)−2 = 0 or, x = +6 Hence, the oxidation state of Cr in CrO2Cl2 is +6
The reagent used in Sandmeyers reaction is (a) CrO2Cl2 (c . . . - Brainly Answer: please mark me as brainlist Explanation: The reagent used in Sandmeyer's reaction is: (c) Cu₂Cl₂ (Copper (I) chloride) Explanation: Sandmeyer's reaction involves the conversion of an aryl diazonium salt into an aryl halide using a copper (I) halide The general form of the reaction is: ArN2+X− + CuX → ArX + N2 +Cu+ Here, Ar represents the aryl group, X is the halide ion, and
Oxidation state of Chromium in CrO2Cl2 - Brainly Oxidation state of Chromium in CrO2Cl2 : Here both O are double bonded with Cr and both Cl are bonded with single bond Hence the oxidation state of O will be -2 and oxidation state of Cl will be -1 Assume the oxidation state of Cr as x; X + (2 × −2) + (2 × −1) = 0 X − 4− 2 = 0 X = 4 + 2 X = +6 Hence the oxidation state of Cr will be +6 here The structure of CrO2Cl2 is as given in
If a mixture of NaCl, conc. H2SO4 and K2Cr2O7 is heated in a . . . - EduRev P and Q are, respectively:a)CrO2Cl2 and Ag2Cr2O7b)Na2 [CrOCl5] and Ag2CrO4c)Na2 [CrOCl5] and Ag2Cr2O7d)CrO2Cl2 and Ag2CrO4Correct answer is option 'D' Can you explain this answer?, a detailed solution for If a mixture of NaCl, conc H2SO4 and K2Cr2O7 is heated in a dry test tube, a red vapour (P) is formed